Chances of US choosing to kidnap president of a nation in which a politician just won Nobel Prize: 1 in 36,000
Calculations do not take into account a psychopathic American president who is pissed that he didn't win the Nobel Peace Prize.
Calculations by ChatGPT
A U.S. president-kidnapping intervention happens somewhere in the world within a 4-month window (event A) and the target country is the one that, in that same 4-month window, has a politician who just won the Nobel Peace Prize (event B).
A clean way to express that is:
P(A∩B)=P(A)×P(B∣A)
Where:
P(A) = chance the U.S. kidnaps/seizes a sitting president in a randomly selected 4-month window.
P(B∣A) = chance that, given such an event happens somewhere, it happens to the Nobel-country (the single Nobel-country created by that years Nobel announcement).
1) Estimating
P(A): how often does the U.S. seize a president in a 4-month window?
Using a straightforward historical base-rate approach:
Nobel Peace Prize begins in 1901.
From 1901 to early 2026 is ~125 years ≈ 375 four-month windows.
How many U.S. actions clearly match military intervention resulting in capture/seizure of the top leader?
Panama / Noriega: Noriega surrendered and was taken into U.S. custody on Jan 3, 1990 (after the 1989 invasion).
That gives 2 events over ~375 four-month windows:
=0.00533≈0.533%
So, about 0.5% per 4-month window (roughly 1 in 188 windows), using this strict definition.
(If you include disputed/ambiguous cases, the estimate rises, but then youre changing the definition.)
2) Estimating
P(B∣A): if such an event happens, whats the chance it hits the Nobel-country?
With 193 UN member states, the probability the target matches the one Nobel-country is:
= 0.518%
3) Joint probability
P(A∩B)
Multiply the two:
0.00533
×
0.00518
0.0000276
P(A∩B)≈0.00533×0.00518≈0.0000276
As a percent:
0.0000276
=
0.00276
%
0.0000276=0.00276%
As 1 in X:
0.0000276
≈
36,200
1/0.0000276≈36,200
Result (under the explicit base-rate + uniform-target model)
≈ 0.0028% per 4-month window (about 1 in 36,000).